A) \[\left( 1+3z \right)\left( 1-3z \right)\]
B) \[{{\left( z+3 \right)}^{2}}\]
C) \[{{\left( 3z-1 \right)}^{2}}\]
D) \[{{\left( z-3 \right)}^{2}}\]
Correct Answer: C
Solution :
(c): \[1-6z+9{{z}^{2}}or\,9{{z}^{2}}-6z+1\] or\[{{\left( 3z \right)}^{2}}-2\times 3z\times 1+{{\left( 1 \right)}^{2}}\] or \[{{\left( 3z-1 \right)}^{2}}.\]
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