A) \[(2b-3a)\]
B) \[(3a-b)\]
C) \[(4a-3b)\]
D) \[(-3a+4b)\]
Correct Answer: D
Solution :
We have, \[4(x+y)(3a-b)+6(x+y)(2b-3a)\] \[=2(x+y)[2(3a-b)+3(2b-3a)]\] \[=2(x+y)[6a-2b+6b-9a]\] \[=2(x+y)[-3a+4b]\]
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