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8th Class Mathematics Exponents and Power Question Bank Exponents and Powers

  • question_answer
    Solve \[{{\left( {{4}^{5}} \right)}^{x}}={{\left( {{4}^{4}} \right)}^{x}}\div {{4}^{2}}\]

    A)  \[x=4\]                        

    B)  \[x=-2\]  

    C)  \[x=-3\]                       

    D)  \[x=2\]

    Correct Answer: B

    Solution :

    (b) \[{{\left( {{4}^{5}} \right)}^{x}}={{4}^{5x}}\] \[{{\left( {{4}^{4}} \right)}^{x}}={{4}^{4x}}\] \[\therefore ={{4}^{5x}}={{4}^{4x-2}}\Rightarrow 5x=4x-2\] \[\Rightarrow x=-2\]


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