A) \[\frac{19}{64}\]
B) \[\frac{64}{19}\]
C) \[\frac{27}{16}\]
D) \[\frac{16}{27}\]
Correct Answer: A
Solution :
\[\left. \left\{ {{\left( \frac{1}{3} \right)}^{-3}}-{{\left( \frac{1}{2} \right)}^{-3}} \right. \right\}\div {{\left( \frac{1}{4} \right)}^{-3}}\] \[=\left\{ {{(3)}^{3}}-{{(2)}^{3}} \right\}\div {{\left( 4 \right)}^{3}}=\left\{ 27-8 \right\}\div 64=\frac{19}{64}\]
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