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8th Class Mathematics Exponents and Power Question Bank Exponents and Powers

  • question_answer
    If \[x={{\left( \frac{3}{2} \right)}^{2}}\times {{\left( \frac{2}{3} \right)}^{-4}}\]then value of \[{{\mathbf{x}}^{\mathbf{2}}}\]is

    A)  \[{{\left( \frac{2}{3} \right)}^{11}}\]                

    B)  \[{{\left( \frac{2}{3} \right)}^{12}}\]

    C)  \[{{\left( \frac{2}{3} \right)}^{7}}\]                  

    D)  \[{{\left( \frac{2}{3} \right)}^{3}}\]

    Correct Answer: B

    Solution :

    (b) \[x={{\left( \frac{3}{2} \right)}^{2}}\times {{\left( \frac{2}{3} \right)}^{-4}}\] \[={{\left( \frac{3}{2} \right)}^{2}}\times {{\left( \frac{2}{3} \right)}^{-4}}={{\left( \frac{3}{2} \right)}^{6}}\] \[\therefore {{x}^{-2}}={{\left( \frac{3}{2} \right)}^{-12}}={{\left( \frac{2}{3} \right)}^{12}}\].


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