A) \[x=\frac{3}{4}\]
B) \[x=\frac{2}{3}\]
C) \[x=\frac{5}{6}\]
D) \[x=\frac{3}{2}\]
Correct Answer: D
Solution :
(d) \[{{\left( {{9}^{2}} \right)}^{2x}}={{\left( {{9}^{3}} \right)}^{2}}\] \[\Rightarrow {{9}^{4x}}={{9}^{6}}\Rightarrow 4x=6\Rightarrow x=\frac{3}{2}\]
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