A) 5
B) 7
C) 8
D) 12
Correct Answer: D
Solution :
\[72={{2}^{3}}\times {{3}^{2}}\] (Prime factors are 1, 2, 3); Prime factors are prime numbers \[192={{2}^{6}}\times {{3}^{1}}\] (Prime factors are 1, 2, 3) \[\therefore \] The required sum is\[3+2+6+1=12\]You need to login to perform this action.
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