A) \[\frac{x}{y}+{{e}^{{{x}^{3}}}}=c\]
B) \[\frac{x}{y}-{{e}^{{{x}^{3}}}}=0\]
C) \[\frac{-x}{y}+{{e}^{{{x}^{3}}}}=0\]
D) None of these
Correct Answer: A
Solution :
\[ydx-xdy+3{{x}^{2}}{{y}^{2}}{{e}^{{{x}^{3}}}}dx=0\] \[\frac{ydx-xdy}{{{y}^{2}}}+3{{x}^{2}}{{e}^{{{x}^{3}}}}dx=0\] Þ \[d\left( \frac{x}{y} \right)+d{{e}^{{{x}^{3}}}}=0\] On integrating, we get \[\frac{x}{y}+{{e}^{{{x}^{3}}}}=c\]
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