A) 25%
B) 50%
C) 100%
D) 125%
Correct Answer: D
Solution :
Kinetic energy \[E=\frac{1}{2}m{{v}^{2}}\] \[\therefore \,\,\,\frac{\Delta E}{E}\times 100=\frac{{{{{v}'}}^{2}}-{{v}^{2}}}{{{v}^{2}}}\times 100\] \[=[{{(1.5)}^{2}}-1]\times 100\] \[\therefore \,\,\frac{\Delta E}{E}\times 100=125%\]
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