A) \[\pm \]17%
B) \[\pm \]16%
C) \[\pm \]19%
D) \[\pm \]25%
Correct Answer: B
Solution :
\[H={{I}^{2}}R\,t\] \[\therefore \,\,\,\frac{\Delta H}{H}\times 100=\left( \frac{2\Delta I}{I}+\frac{\Delta R}{R}+\frac{\Delta t}{t} \right)\times 100\] \[=(2\times 3+4+6)%\] \[=16%\]
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