A) - 3
B) - 1
C) 3
D) 1
Correct Answer: A
Solution :
Given equation of pair of lines is \[6{{x}^{2}}-xy+4c{{y}^{2}}=0\] ?..(i) Slope of line \[3x+4y=0\]is \[\frac{-3}{4}={{m}_{1}}\] (say) Product of slopes of lines \[{{m}_{1}}{{m}_{2}}=\frac{a}{b}=\frac{6}{4c}=\frac{3}{2c}\] \[\therefore \]\[{{m}_{2}}=\frac{3/2c}{-3/4}=\frac{-2}{c}\]. Also, \[{{m}_{1}}+{{m}_{2}}=\frac{-2h}{b}=\frac{1}{4c}\] \[\Rightarrow \,\frac{-3}{4}-\frac{2}{c}=\frac{1}{4c}\Rightarrow -3c-8=1\Rightarrow c=-3\].
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