A) 5/3
B) 10/3
C) 3/2
D) 3/10
Correct Answer: B
Solution :
\[\left| \begin{matrix} 1 & k/2 & -5/2 \\ k/2 & 1 & -7/2 \\ -5/2 & -7/2 & 6 \\ \end{matrix} \right|=0\] \[\Rightarrow \]\[\left( 6-\frac{49}{4} \right)-\frac{k}{2}\left( \frac{6k}{2}-\frac{35}{4} \right)-\frac{5}{2}\left( -\frac{7k}{4}+\frac{5}{2} \right)=0\] Þ \[6{{k}^{2}}-35k+50=0\] Þ \[k=\frac{10}{3}\].
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