A) \[{{h}^{2}}=ab\]
B) \[h=a+b\]
C) \[8{{h}^{2}}=9ab\]
D) \[9{{h}^{2}}=8ab\]
Correct Answer: C
Solution :
Here, \[{{m}_{1}}+{{m}_{2}}=\frac{-2h}{b}\] and \[{{m}_{1}}{{m}_{2}}=\frac{a}{b}\] Given that \[{{m}_{1}}=2{{m}_{2}}\] \[\therefore \]\[3{{m}_{2}}=\frac{-2h}{b}\] and \[2m_{2}^{2}=\frac{a}{b}\] Þ \[2{{\left( \frac{-2h}{3b} \right)}^{2}}=\frac{a}{b}\]Þ \[8{{h}^{2}}=9ab\].
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