A) \[2{{x}^{2}}-xy-6{{y}^{2}}=0\]
B) \[6{{x}^{2}}-xy+2{{y}^{2}}=0\]
C) \[6{{x}^{2}}-xy-2{{y}^{2}}=0\]
D) \[2{{x}^{2}}+xy-6{{y}^{2}}=0\]
Correct Answer: A
Solution :
Equation is \[2{{x}^{2}}-xy-6{{y}^{2}}+7x+21y-15=0\] Therefore, equation of lines parallel to given lines and passes through origin is homogeneous 2nd degree equation i.e., \[2{{x}^{2}}-xy-6{{y}^{2}}=0.\]
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