A) \[b{{m}^{2}}+2hm+a=0\]
B) \[b{{m}^{2}}+2hm-a=0\]
C) \[a{{m}^{2}}+2hm+b=0\]
D) \[b{{m}^{2}}-2hm+a=0\]
Correct Answer: A
Solution :
Substituting the value of y in the equation\[a{{x}^{2}}+2hxy+b{{y}^{2}}=0\]. \[\Rightarrow a{{x}^{2}}+2h(mx)x+b{{(mx)}^{2}}=0\]\[\Rightarrow a+2hm+b{{m}^{2}}=0\] .
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