A) \[a=0\] or \[b=c\]
B) \[a=b\] or \[a=c\]
C) \[c=0\] or \[a=b\]
D) \[a=b+c\]
Correct Answer: A
Solution :
The lines are coincident, if \[{{H}^{2}}-AB=0,\] so \[{{\left\{ \frac{a(b+c)}{2} \right\}}^{2}}-{{a}^{2}}(bc)=0\] Þ \[{{a}^{2}}{{(b-c)}^{2}}=0\] Þ a = 0 or\[b=c\].
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