JEE Main & Advanced Mathematics Pair of Straight Lines Question Bank Equation of Pair of Straight Lines

  • question_answer
    The equation of the perpendiculars drawn from the origin to the lines represented by the equation \[2{{x}^{2}}-10xy+12{{y}^{2}}+5x-16y-3=0\] is

    A)            \[6{{x}^{2}}+5xy+{{y}^{2}}=0\]                                        

    B)            \[6{{y}^{2}}+5xy+{{x}^{2}}=0\]

    C)            \[6{{x}^{2}}-5xy+{{y}^{2}}=0\]                                         

    D)            None of these

    Correct Answer: A

    Solution :

               We know that the equation of perpendicular drawn from origin on \[a{{x}^{2}}+2hxy+b{{y}^{2}}+2gx+2fy+c=0\] is \[b{{x}^{2}}-2hxy+a{{y}^{2}}=0\].                    Therefore, the required equation is given by                    \[12{{x}^{2}}+10xy+2{{y}^{2}}=0\]or\[6{{x}^{2}}+5xy+{{y}^{2}}=0\].


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