A) 1 : 1
B) 1 : 2
C) 2 : 1
D) 2 : 3
Correct Answer: A
Solution :
\[{{\tau }_{\max }}=\frac{16T}{\pi {{d}^{3}}}\] \[{{\sigma }_{\max }}={{\sigma }_{\max }}\,\,for\theta =45{}^\circ \]
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