A) \[3.44\times {{10}^{-\,4}}\]
B) \[3.84\times {{10}^{-\,4}}\]
C) \[4\times {{10}^{-\,4}}\]
D) \[4.56\times {{10}^{-\,4}}\]
Correct Answer: A
Solution :
\[{{\sigma }_{\theta }}=80\,MPa,\] \[E=2\times {{10}^{5}}MPa,\] n = 0.28 \[{{\sigma }_{1}}=\frac{{{\sigma }_{\theta }}}{2}=40\,MPa\] \[{{\varepsilon }_{\theta }}=\frac{1}{E}[{{\sigma }_{\theta }}-v{{\sigma }_{1}}]\] \[=\frac{{{\sigma }_{\theta }}}{E}[1-0.5v]\] \[=\frac{80}{2\times {{10}^{5}}}[1-0.5\times 0.28]=3.44\times {{10}^{-\,4}}\]
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