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Railways NTPC (Technical Ability) Engineering Mechanics and Strength of Materials Question Bank Engineering Mechanics

  • question_answer
                          A train of weight \[200\times {{10}^{4}}N\] is running on  horizontal track at a constant speed of 10 m/s, overcoming a constant frictional force of \[200\,\,\times \,\,10\,N.\] What is the power of the engine drinking the train

    A) 800 kW            

    B) 1200 kW                           

    C) 200 kW            

    D) 400 kW        

    Correct Answer: C

    Solution :

    Power of the engine = Frictional force\[\times \]speed \[=\frac{20\times {{10}^{3}}\times 10}{{{10}^{3}}}=200\,kW\]


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