A) \[\sqrt{m}\]
B) \[1\sqrt{m}\]
C) \[m\]
D) \[1\,m\]
Correct Answer: B
Solution :
\[a=\frac{F}{m}\] \[{{v}^{2}}-{{u}^{2}}=2as\] \[{{v}^{2}}=2as=2as\,\frac{2Fs}{m}\] \[v\alpha \,\frac{1}{\sqrt{m}}\]
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