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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Energy of Simple Harmonic Motion

  • question_answer
    The potential energy of a particle with displacement X is U(X). The motion is simple harmonic, when (K is a positive constant)                                                                          [CPMT 1982]

    A)            \[U=-\frac{K{{X}^{2}}}{2}\]    

    B)            \[U=K{{X}^{2}}\]

    C)            \[U=K\]                                  

    D)            \[U=KX\]

    Correct Answer: A

    Solution :

                       \[F=-\,kx\] Þ \[dW=Fdx=-\,kxdx\]            So \[\int_{\,0}^{\,W}{dW}=\int_{\,0}^{\,x}{-kx\,dx}\]Þ \[W=U=-\frac{1}{2}k{{x}^{2}}\]


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