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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Energy of Simple Harmonic Motion

  • question_answer
    The amplitude of a particle executing SHM is made three-fourth keeping its time period constant. Its total energy will be                                                                                        [RPMT 2004]

    A)            \[\frac{E}{2}\]                      

    B)            \[\frac{3}{4}E\]

    C)            \[\frac{9}{16}E\]                 

    D)            None of these

    Correct Answer: C

    Solution :

                       \[E=\frac{1}{2}m{{\omega }^{2}}{{a}^{2}}\]Þ\[\frac{{{E}'}}{E}=\frac{{{{{a}'}}^{2}}}{{{a}^{2}}}\]Þ\[\frac{{{E}'}}{E}=\frac{{{\left( \frac{3}{4}a \right)}^{2}}}{{{a}^{2}}}\]            \[\left( \because {a}'=\frac{3}{4}a \right)\] Þ\[{E}'=\frac{9}{16}E\]


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