A) 1 cm
B) \[\sqrt{2}\]cm
C) 3 cm
D) \[2\sqrt{2}\]cm
Correct Answer: D
Solution :
Let x be the point where K.E. = P.E. Hence \[\frac{1}{2}m{{\omega }^{2}}({{a}^{2}}-{{x}^{2}})=\frac{1}{2}m{{\omega }^{2}}{{x}^{2}}\] Þ \[2{{x}^{2}}={{a}^{2}}\] Þ \[{{T}_{1}}=2s\]
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