A) (1) and (2) are correct
B) (2) and (3) are correct
C) (1) and (3) are correct
D) (1), (2) and (3) are correct
Correct Answer: A
Solution :
\[E=\frac{1}{2}m{{a}^{2}}{{\omega }^{2}}\]\[=\frac{1}{2}m{{a}^{2}}\left( \frac{4{{\pi }^{2}}}{{{T}^{2}}} \right)\]Þ \[E\propto \frac{{{a}^{2}}}{{{T}^{2}}}\]You need to login to perform this action.
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