A) \[a/4\]
B) \[a/3\]
C) \[a/2\]
D) \[2a/3\]
Correct Answer: C
Solution :
\[\frac{U}{{{U}_{\max }}}=\frac{\frac{1}{2}m{{\omega }^{2}}{{y}^{2}}}{\frac{1}{2}m{{\omega }^{2}}{{a}^{2}}}\]Þ \[\frac{1}{4}=\frac{{{y}^{2}}}{{{a}^{2}}}\] Þ \[y=\frac{a}{2}\]
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