JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank EM Waves

  • question_answer
    A TV tower has a height of 100 m. The average population density around the tower is 1000 per km2. The radius of the earth is \[6.4\times {{10}^{6}}\]m. the population covered by the tower is

    A)            \[2\times {{10}^{6}}\]      

    B)            \[3\times {{10}^{6}}\]

    C)            \[4\times {{10}^{6}}\]      

    D)            \[6\times {{10}^{6}}\]

    Correct Answer: C

    Solution :

                       Population covered = 2phR ´ Population density = 2p ´ 100 ´ 6.4 ´ 106 ´ \[\frac{1000}{{{({{10}^{3}})}^{2}}}\]= 4 ´ 106


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