A) 30-300
B) 3-30
C) 300-3000
D) 3-3000
Correct Answer: A
Solution :
\[v=\frac{C}{\lambda }\Rightarrow {{v}_{1}}=\frac{3\times {{10}^{8}}}{1}\] = \[3\times {{10}^{8}}Hz=300\ MHz\] and \[{{v}_{2}}=\frac{3\times {{10}^{8}}}{10}\]=\[3\times {{10}^{7}}Hz=30MHz\]
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