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JEE Main & Advanced Mathematics Conic Sections Question Bank Ellipse

  • question_answer
    The centre of the ellipse\[\frac{{{(x+y-2)}^{2}}}{9}+\frac{{{(x-y)}^{2}}}{16}=1\] is  [EAMCET 1994]

    A)            (0, 0)                                         

    B)            (1, 1)

    C)            (1, 0)                                         

    D)            (0, 1)

    Correct Answer: B

    Solution :

               The centre of the given ellipse is the point of intersection of the lines \[x+y-2=0\]and \[x-y=0\]i.e.,(1,1).


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