A) \[1/\sqrt{3}\]
B) \[\sqrt{3}/2\]
C) \[1/2\]
D) None of these
Correct Answer: B
Solution :
\[4{{x}^{2}}-8x+{{y}^{2}}+2y+1=0\] Þ \[{{(2x-2)}^{2}}+{{(y+1)}^{2}}=-1+4+1\] Þ \[\frac{{{(x-1)}^{2}}}{1}+\frac{{{(y+1)}^{2}}}{4}=1\] Þ \[e=\sqrt{1-\frac{1}{4}}\] Þ \[e=\frac{\sqrt{3}}{2}\].
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