A) \[3/\sqrt{7}\]
B) 7/16
C) 3/4
D) 4/3
Correct Answer: C
Solution :
\[\frac{{{x}^{2}}}{\frac{112}{16}}+\frac{{{y}^{2}}}{\frac{112}{7}}=1\]. Therefore,\[e=\sqrt{1-\frac{112}{16}.\frac{7}{112}}=\frac{3}{4}\]
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