A) Minor axis
B) Semi-minor axis
C) Major axis
D) Semi-major axis
Correct Answer: D
Solution :
\[e=\frac{1}{\sqrt{2}}\]; Latus rectum \[=\frac{2{{b}^{2}}}{a}=\frac{2{{a}^{2}}}{a}\left( 1-\frac{1}{2} \right)=a\] i.e., semi-major axis.
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