JEE Main & Advanced Mathematics Conic Sections Question Bank Ellipse

  • question_answer
    The point (4, ?3) with respect to the ellipse \[4{{x}^{2}}+5{{y}^{2}}=1\] [Orissa JEE 2005]

    A)            Lies on the curve                       

    B)            Is inside the curve

    C)            Is outside the curve                  

    D)            Is focus of the curve

    Correct Answer: C

    Solution :

               Using the condition the point \[({{x}_{1}},\,{{y}_{1}})\] lies                    (i) On the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}-1=0\] if                    \[\frac{x_{1}^{2}}{{{a}^{2}}}+\frac{y_{1}^{2}}{{{b}^{2}}}-1=0\]            (ii) Outside the ellipse if \[\frac{x_{1}^{2}}{{{a}^{2}}}+\frac{y_{1}^{2}}{{{b}^{2}}}-1>0\]            (iii) Inside the ellipse if \[\frac{x_{1}^{2}}{{{a}^{2}}}+\frac{y_{1}^{2}}{{{b}^{2}}}-1<0\]            Given ellipse is \[\frac{{{x}^{2}}}{1/4}+\frac{{{y}^{2}}}{1/5}=1\]            \ \[\frac{16}{1/4}+\frac{9}{1/5}-1=64+45-1>0\]            Point (4, ?3) lies outside the ellipse.


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