JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Elevation of boiling point of the solvent

  • question_answer
    The rise in the boiling point of a solution containing 1.8 gram of glucose in \[100g\] of a solvent in \[{{0.1}^{o}}C\]. The molal elevation constant of the liquid is        [CPMT 1999]

    A)                 0.01 \[K/m\]          

    B)                 \[0.1\,K/m\]

    C)                 \[1\,K/m\]               

    D)             \[10\,K/m\]

    Correct Answer: C

    Solution :

                \[{{K}_{b}}=\frac{\Delta {{T}_{b}}}{m}=\frac{0.1\times 100}{\frac{1.8}{180}\times 1000}=1\,K/m\].


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