A) 11
B) 10
C) 12
D) \[-10\]
Correct Answer: B
Solution :
| [b] Given, \[x=11\], \[\therefore \]\[{{x}^{5}}-12{{x}^{4}}+12{{x}^{3}}-12{{x}^{2}}+12x-1\] \[={{x}^{4}}(x-12)+12{{x}^{2}}(x-1)+12x-1\] \[={{x}^{4}}(11-12)+{{x}^{2}}(11-1)+12\times 11-1\] \[={{x}^{4}}(-1)+12{{x}^{2}}(10)+132-1\] \[={{x}^{4}}+120{{x}^{2}}+131={{x}^{2}}({{x}^{2}}+120+131)\] \[={{(11)}^{2}}[-\,{{(11)}^{2}}+120]+131=121\,\,(-121+120)+131\] \[=121x-1+131=-121+131=10\] |
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