A) \[1\]
B) \[2\]
C) \[2\sqrt{2}\]
D) \[3\sqrt{3}\]
Correct Answer: B
Solution :
| [b] Given,\[x=3+2\sqrt{2}\] \[\Rightarrow \] \[x={{(\sqrt{2}+1)}^{2}}\] \[\therefore \] \[\sqrt{x}=(\sqrt{2}+1)\] Now, \[\sqrt{x}-\frac{1}{\sqrt{x}}=(\sqrt{2}+1)-\frac{1}{\sqrt{2}+1}\] \[=(\sqrt{2}+1)-\frac{(\sqrt{2}-1)}{(\sqrt{2}+1)(\sqrt{2}-1)}\] \[=(\sqrt{2}+1)-(\sqrt{2}-1)\] \[=(\sqrt{2}+1-\sqrt{2}+1)=2\] |
You need to login to perform this action.
You will be redirected in
3 sec
