A) \[Be{{F}_{2}}\]
B) \[Sr{{F}_{2}}\]
C) \[Ca{{F}_{2}}\]
D) \[Mg{{F}_{2}}\]
Correct Answer: B
Solution :
The solubility order is : \[Be{{F}_{2}}>Mg{{F}_{2}}>\]\[Ca{{F}_{2}}>Sr{{F}_{2}}\] so \[Sr{{F}_{2}}\] is least soluble.
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