A) (ii) > (iii) > (iv) > (i)
B) (iii) > (ii) > (iv) > (i)
C) (iv) > (iii) > (ii) > (i)
D) (i) > (ii) > (iii) > (iv)
Correct Answer: A
Solution :
Net resistance, \[{{R}_{AB}}=\frac{R}{3}\] Power dissipated. \[{{P}_{AB}}={{l}^{2}}{{R}_{AB}}{{l}^{2}}\frac{R}{3}\] (ii) Net resistance, \[{{R}_{AB}}=3R\] Power dissipated. \[{{P}_{AB}}={{l}^{2}}{{R}_{AB}}={{l}^{2}}(3R)=3{{l}^{2}}R\] (iii) Net resistance, \[{{R}_{AB}}=\frac{R}{2}+R=\frac{3}{2}R\] Power dissipated. \[{{P}_{AB}}={{l}^{2}}{{R}_{AB}}={{l}^{2}}\left( \frac{3}{2}R \right)=\frac{3}{2}{{l}^{2}}R\] (iv) Net resistance \[\frac{1}{{{R}_{AB}}}=\frac{1}{2R}+\frac{1}{R}=\frac{3}{2R}\] or \[{{R}_{AB}}=\frac{2}{3}R\] Power dissipated. \[{{P}_{AB}}={{l}^{2}}{{R}_{AB}}={{l}^{2}}\left( \frac{2}{3}R \right)=\frac{2}{3}{{l}^{2}}R\] Thus, (ii) > (iii) > (iv) > (i)You need to login to perform this action.
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