A) \[4.2\times {{10}^{42}}\]
B) \[4.2\times {{10}^{-42}}\]
C) \[\text{2}\text{.4 }\times \text{ 1}0\text{24}\]
D) \[\text{2}.\text{4 }\times \text{ 1}0.\text{24}\]
Correct Answer: A
Solution :
We know,\[{{F}_{e}}=9\times {{10}^{9}}\frac{e\times e}{{{r}^{2}}}\] and \[{{F}_{G}}=6.6\times {{10}^{-11}}\frac{{{m}_{e}}\times {{m}_{e}}}{{{r}^{2}}}\] \[\therefore \] \[\frac{{{F}_{e}}}{{{F}_{G}}}=\frac{9\times {{10}^{9}}}{6.6\times {{10}^{-11}}}{{\left( \frac{e}{{{m}_{e}}} \right)}^{2}}\] \[=\frac{9\times {{10}^{9}}}{6.6\times {{10}^{-11}}}\times \frac{{{(1.6\times {{10}^{-19}})}^{2}}}{{{(9.1\times {{10}^{-31}})}^{2}}}\] \[=\mathbf{4}\mathbf{.2\times 1}{{\mathbf{0}}^{\mathbf{42}}}\]
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