A) \[1\times {{10}^{-8}}\]
B) \[1\times {{10}^{-4}}\]
C) \[1\times {{10}^{-6}}\]
D) \[{{10}^{-5}}\]
Correct Answer: A
Solution :
\[K=\frac{{{\alpha }^{2}}C}{1-\alpha };\,\,\alpha =\frac{0.01}{100}\approx 1\,\,\,\therefore \,\,K={{\alpha }^{2}}C={{\left[ \frac{0.01}{100} \right]}^{2}}\times 1\] \[=1\times {{10}^{-8}}\].
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