A) 1
B) \[\sqrt{\frac{2{{m}_{e}}}{{{m}_{\alpha }}}}\]
C) \[\sqrt{\frac{{{m}_{e}}}{{{m}_{\alpha }}}}\]
D) \[\sqrt{\frac{{{m}_{e}}}{2{{m}_{\alpha }}}}\]
Correct Answer: D
Solution :
Momentum \[p=\sqrt{2mK}\,;\] where K = kinetic energy = Q.V Þ\[p=\sqrt{2mQV}\]Þ\[p\propto \sqrt{mQ}\,\Rightarrow \,\frac{{{p}_{e}}}{{{p}_{\alpha }}}=\sqrt{\frac{{{m}_{e}}{{Q}_{e}}}{{{m}_{\alpha }}{{Q}_{\alpha }}}}\]\[=\sqrt{\frac{{{m}_{e}}}{2{{m}_{\alpha }}}}\]
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