A) \[-\frac{Q}{2}\]
B) \[-\frac{Q}{4}\]
C) \[+\frac{Q}{4}\]
D) \[+\frac{Q}{2}\]
Correct Answer: B
Solution :
Suppose in the following figure, equilibrium of charge B is considered. Hence for it's equilibrium \[|{{F}_{A}}|\,=\,|{{F}_{C}}|\] Þ \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{Q}^{2}}}{4{{x}^{2}}}=\]\[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{qQ}{{{x}^{2}}}\] Þ \[q=\frac{-\,Q}{4}\]You need to login to perform this action.
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