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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    The work done in bringing a 20 coulomb charge from point A to point B for distance 0.2m is 2J. The potential difference between the two points will be (in volt) [RPET 1999; MP PMT 2002; AIEEE 2002]

    A)            0.2 

    B)            8

    C)            0.1 

    D)            0.4

    Correct Answer: C

    Solution :

                 By using \[W=Q.\Delta V\]Þ \[\Delta V=\frac{2}{20}=0.1\,volt\]


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