A) \[1.6\times {{10}^{19}}\]
B) \[1.6\times {{10}^{-29}}\]
C) \[3.2\times {{10}^{19}}\]
D) \[3.2\times {{10}^{29}}\]
Correct Answer: B
Solution :
\[p=q\times \left( \text{2}l \right)\text{ }=\text{ 1}.\text{6}\times \text{1}{{0}^{\text{19}}}\times \text{1}{{0}^{\text{1}0}}=\text{ 1}.\text{6}\times \text{1}{{0}^{\text{29}}}C-m\]
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