A) \[k.\frac{\overrightarrow{p}\times \overrightarrow{r}}{{{r}^{2}}}\]
B) \[k.\frac{\overrightarrow{p}\times \overrightarrow{r}}{{{r}^{3}}}\]
C) \[k.\frac{\overrightarrow{p}\cdot \overrightarrow{r}}{{{r}^{2}}}\]
D) \[k.\frac{\overrightarrow{p}\cdot \overrightarrow{r}}{{{r}^{3}}}\]
Correct Answer: D
Solution :
Potential due to dipole in general position is given by \[V=\frac{k.p\cos \theta }{{{r}^{2}}}\] \[\Rightarrow \]\[V=\frac{k.p\cos \theta \,r}{{{r}^{3}}}=\frac{k.\,(\vec{p}.\vec{r})}{{{r}^{3}}}\]
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