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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Dipole

  • question_answer
    The distance between \[{{H}^{+}}\] and \[C{{l}^{-}}\] ions in HCl molecule is 1.28 Å. What will be the potential due to this dipole at a distance of 12 Å on the axis of dipole [MP PMT 2002]

    A)            0.13 V

    B)            1.3 V

    C)            13 V                                         

    D)            130 V

    Correct Answer: A

    Solution :

                       \[V=9\times {{10}^{9}}.\frac{p}{{{r}^{2}}}\]     \[=9\times {{10}^{9}}\times \frac{(1.6\times {{10}^{-19}})\times 1.28\times {{10}^{-10}}}{{{(12\times {{10}^{-10}})}^{2}}}\]= 0.13V                    


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