JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Dipole

  • question_answer
    Two charges\[+3.2\times {{10}^{-19}}\] and \[-3.2\times {{10}^{-19}}C\] placed at \[2.4{AA}\] apart form an electric dipole. It is placed in a uniform electric field of intensity \[4\times {{10}^{5}}\,volt/m\]. The electric dipole moment is

    A)                    \[15.36\times {{10}^{-29}}\ coulomb\times m\]

    B)                    \[15.36\times {{10}^{-19}}\ coulomb\times m\]

    C)                    \[7.68\times {{10}^{-29}}\ coulomb\times m\]

    D)                    \[7.68\times {{10}^{-19}}\ coulomb\times m\]

    Correct Answer: C

    Solution :

                        Dipole moment p = q (2l) \[=3.2\times {{10}^{-19}}\times (2.4\times {{10}^{-10}})=7.68\times {{10}^{-29}}C\text{-}m\]


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