A) \[\frac{1}{4}\]
B) \[\frac{1}{2}\]
C) \[\frac{1}{3}\]
D) \[\frac{1}{8}\]
Correct Answer: A
Solution :
Fractional loss \[=\frac{\Delta U}{U}=\frac{mg(h-{h}')}{mgh}\]\[=\frac{2-1.5}{2}=\frac{1}{4}\]
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