JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Elastic and Inelastic Collision

  • question_answer
    A body of mass 50 kg is projected vertically upwards with velocity of 100 m/sec. 5 seconds after this body breaks into 20 kg and 30 kg.  If 20 kg piece travels upwards with 150 m/sec, then the velocity of other block will be            [RPMT 1999]

    A)          15 m/sec downwards    

    B)          15 m/sec upwards

    C)          51 m/sec downwards    

    D)          51 m/sec upwards

    Correct Answer: A

    Solution :

             Velocity of 50 kg. mass after 5 sec of projection \[v=u-gt\]\[=100-9.8\times 5=51\ m/s\] At this instant momentum of body is in upward direction \[{{P}_{\text{initial}}}=50\times 51=2550\ kg-m/s\] After breaking 20 kg piece travels upwards with 150 m/s let the speed of 30 kg mass is V \[{{P}_{\text{final}}}=20\times 150+30\times V\] By the law of conservation of momentum               \[{{P}_{\text{initial }}}={{P}_{\text{final}}}\]               Þ \[2500=20\times 150+30\times V\Rightarrow V=-15\ m/s\]          i.e. it moves in downward direction.


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