A) B0
B) \[\sqrt{2}\,{{B}_{0}}\]
C) 2 B0
D) \[B_{0}^{2}\]
Correct Answer: B
Solution :
\[{{B}_{H}}=B\sin \varphi \Rightarrow B=\frac{{{B}_{H}}}{\sin \varphi }\]\[\Rightarrow B=\frac{{{B}_{o}}}{\sin {{45}^{o}}}=\sqrt{2}{{B}_{0}}\]
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